Simple way to validate email id field in your application - Test Automation

Suppose your requirement is to validate a textfield in which user provides a email id, here is a simple example on how to do it.

Consider the following requirement for your field validation.

                  1) First 4 characters should be numbers
                  2) Next set of characters until reaching a "@" should be alphabets, followed by the domain as say - gmail.com or yahoo.com etc...

Here is the code to validate it.

public class ValidateEmailField
{
public static void main(String[] args)
{
String inputString = "1234rajacasssss@gmail.com";

Pattern pattern=Pattern.compile("(^[0-9]{4}[A-Za-z]+)@[a-z]+\\.[a-z]+");
Matcher m=pattern.matcher(inputString);

System.out.println(inputString);

if (!m.matches())
{
System.out.println("Invalid Email Id entered");
}
else
System.out.println("Email Id is valid.");
}

You can give different values for input string and verify.

How to remove multiple spaces from a string?

Generally, we use trim() to remove white spaces in a string. Suppose if you have a string content with multiple white spaces between words rather than the intended single space, we have to remove those additional spaces in order to continue using the String for further manipulation.

We have the following ways to achieve this.

1) With the help of StringTokenizer class.

    Example code:

 package basics;

import java.util.StringTokenizer;

public class StringTokenizing {

 public static void main(String a[]){
         String str = "My   name is Cassian    Raja   ";
         StringTokenizer st = new StringTokenizer(str, " ");
         StringBuffer sb = new StringBuffer();
         while(st.hasMoreElements()){
             sb.append(st.nextElement()).append(" ");
         }
         System.out.println(sb.toString().trim());
    }
}


Result:
--------

My name is Cassian Raja


 How it works?

StringTokenizer splits the String str using the delimiter as " " (a white space) and stores the splitted words as tokens into st. Loop through each token and add each word into a string buffer object along with a single whitespace to separate each word(token). Finally use trim() to remove the white space at the end of the string and print it.

StringTokenizer is a legacy class and it is being used only for compatibilitypurposes and we have to avoid it in or new code. Instead, we can use String's
split() method to achieve this task.


2. With the help of split() method.

Using split() method will split the string into basic tokens with delimiter as spaces. 


        Example code:

        package basics;

        import java.util.StringTokenizer;

        public class StringTokenizing {

     public static void main(String a[]){
         String str = "My   name is Cassian    Raja   ";
    String str1[] = str.split("\\s+");
         String newString = "";
         
         for(int i=0; i<str1.length; i++){
          newString = newString.concat(str1[i] + " ");
         }
         System.out.println(newString.trim());

          }
       }

 Result:
--------
My name is Cassian Raja


     Here, we use the regex pattern "\\s+" to denote multiple white spaces (more than one) as the delimiter to split the words in the string.